two questions 1. a shark is able to detect the presence of electric fields as sm
ID: 1320482 • Letter: T
Question
two questions
1. a shark is able to detect the presence of electric fields as small as 1.0V/m. To get an idea of the magnitude of this field, suppose you have a parallel plate capacitor connected to a 1.5 V battery. How far apart must the parallel plates be to have an electric field of 1.0 pV/m between the plates?
2. Two metals spheres have charges of equal magnitude, 3.2 x 10^-14 C, but opposite sign. if the potential difference between the two spheres is 4.0 mV, what is the capacitance? (hint the plates are not parallel, but the definition of capacitance holds.)
Explanation / Answer
1. . The field strength between the plates, away from the edges, is the voltage across the plates divided by the distance between them.
2. C=Q/V = 3.24E-12 or 3.24pF
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