the circuit below has the following values; R=60, voltmeter resistance=300ohms,

Question

the circuit below has the following values; R=60, voltmeter resistance=300ohms, ammeter reading= 0.60amps

1-What will the Voltmeter reading be?

2-what is the current though the voltmeter?

3-what is the current though R.

4- If the voltmeter current is neglected and the 06 amps shwon by the ammeter is assumed to be flowing only through R, what value whould one obtain for the resistance of R?

5-What percent of error in the experimental value of R results if the procdure in 9 is followed? This is to show that sometimes you can neglect the current in the voltmeter?

Explanation / Answer

Part 1)

From Ohms Law...

V = IR

The net resistance is...

1/R = 1/60 + 1/300

R = 50 Ohms

V = (.6)(50)

V = 30 Volts

Part 2)

30 = I(300)

I = .10 Amps

Part 3)

30 = I(60)

I = .5 Amps

Part 4)

V = IR

30 = .6(R)

R = 50 Ohms

Part 5)

I am assuming you meat in part 4 and not part 9. If you meant part 9, this can;t be done since you did not include any info for any parts past 5. If you meant part 4, then...

(50 - 60)/(60) = .167

That is 16.7%

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