For Solving the magnitude of friction, I know it has to be static friction becau

Question

For Solving the magnitude of friction, I know it has to be static friction because it's at rest, and the equation should be fs=Ms*N, which would be 1.5*431.63=647.64, but the answer I got was wrong. Can I also have some help with the second half of the problem? Thank you!

A 44 kg box rests on a level surface. The coefficient of static friction, Mus = 1.5 and the coefficient of kinetic friction, Muk = 1.1. a) What is the magnitude of Gravity on the box from the Earth? 431.64 N b) What is the magnitude of the Normal Force on box from the surface? 431.64 N c) What is the magnitude of Friction on the box from the surface? 647.5 N Miso the Miracle Dog arrives and gives the box a horizontal push. d) If Miso pushes with a force of 453 N, what is the magnitude of Friction on the box from the surface? N e) If Miso?s force on the box is 583 N. What is the magnitude of Friction on the box from the surface? N f) Suppose Miso uses an even larger horizontal force of 646 N. What would be the magnitude of Friction on the box from the surface? N g) If Miso?s force on the box is 712 N, what is the magnitude of Friction on the box from the surface? N

Explanation / Answer

c) Since no horizontal force is acting on the body, frictional force has to be zero.

d) Maximum frictional force= musmg=1.5*44*9.8=646.8 N

     So,if the net external force is less than 646.8 N, friction force will be equal to net external force.

      Frictional Force=453N

e) Frictional Force= 583N

f) Frictinal Force= 646 N

g)Since 712 N> 686.6 N, the box will start moving and kinetic friction will act on it.

                               frictional force= mukmg=1.1*44*9.8=474.32 N

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