A conducting bar of length E moves to the right on two frictionless rails as Sho

Question

A conducting bar of length E moves to the right on two frictionless rails as Shown In the figure below. A uniform magnetic field directed Into the page has a magnitude or 0.290 T. Assume R=8.90 Ohm and l=0.370 m. (a) At what constant speed should the bar move to produce an 8,70.mA current In the resistor? m/s (b) What is direction of the induced current clockwise counterclockwise into the page out of the page (C) At what rate is energy delivered to the resistor? mW (d) Explain the origin or the energy being delivered to the resistor.

Explanation / Answer

a) to produce 8.70 mA current, induced emf E = iR = 8.9- x 8.70 x 10-3 = 0.0774 V

induced emf (according to faraday law and lenz law)
E = - Blv
0.0774 = 0.290 x 0.370 x v
v =0.722 m/s

b) counterclockwise

c) energy = i^2R = (0.0087^2) x8.90 = 6.74 x 10-4 Watt

d) as conducting rod is moving in magnetic field, magnetic flux is genereated and that will
opposes by current generated in resistor.

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