A mortar* crew is positioned near the top of a steep hill. Enemy forces are char

Question

A mortar* crew is positioned near the top of a steep hill. Enemy forces are charging up the hill and it is necessary for the crew to spring into action. Angling the mortar at an angle of theta = 51.0 degree (as shown), the crew fires the shell at a muzzle velocity of 256 feet per second. How far down the hill does the shell strike if the hill subtends an angle = 38.0 degree from the horizontal? (Ignore air friction.) How long will the mortar shell remain in the air? How fast will the shell be traveling when it hits the ground? * The mortar is like a small cannon that launches shells at steep angles.

Explanation / Answer

Best Answer: To make this problem simpler, let

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