when two identical air pucks with repelling magnets are held together on an air

Question

when two identical air pucks with repelling magnets are held together on an air table and released, they end up moving in opposite directions at the same speed, v. assume the mass of one of the pucks is doubled and the procedure is repeated. a) from newtons third law, derive an equation that shows how the final speed of the double mass puck compares with the speed of the single puck. b) Calculate the speed of double mass puck if the single puck moves away at 0.4m/s.. N/B Kindly show me an illustration for B

Explanation / Answer

A) The second (double-mass) puck has half the velocity of the first puck
B) The speed of the double-mass puck is 0.2 (
Method:
If you keep basic concepts in mind, you can just about do this in your head. The two pucks experience the same force for the same time (impulse) and therefore have the same momentum change.

Impulse = change in momentum
Ft = ?mv
?v = Ft/m
The change in velocity is inversely proportional to the mass, so doubling the mass halves the change in velocity.

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