Learning Goal: To practice Problem-Solving Strategy 6.2 for dynamics problems A

Question

Learning Goal: To practice Problem-Solving Strategy 6.2 for dynamics problems A box of mass 3.06kg slides down a rough vertical wall. The gravitational force on the box is 30N. When the box reaches a speed of 2.5m/s, you start pushing on one edge of the box at a 45° angle (use degrees in your calculations throughout this problem with a constant force of magnitude F 23N, as shown in (Figure 1) There is now a frictional force between the box and the wall of magnitude 13N How fast is the box sliding 3.0s Figure 1 of 1 3.2 m/s Hints My Answers Give Up Review Part Correct Your answer 3.22 m/s was either rounded different or used a different number of significant figures than Significant Figures Feedback: required for this part. Assess Part D Assuming that the angle at which you push on the edge of the box is again 450, with what magnitude of force Fp should you push if the box were to slide down the wall at a constant velocity? Note that, in general, the magnitude of the friction force will change if you change the magnitude of the pushing force. Thus, for this part, assume that the magnitude of the friction force is f 0.566 Submit Hints My Answers Give Up Review Part Incorrect, Try Again, 5 attempts remaining Provide Feedback Continue

Explanation / Answer

Here ,

for friction , f = 0.566 Fp

For sliding with constant velocity

mg - Fp*cos(45) - f = 0

3.06 *9.8 - Fp*cos(45) - 0.566 Fp = 0

solving for Fp

Fp = 23.55 N

the magnitude of Fp is 23.55 N

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