The initial momentum of the steel ball at the bottom of the ramp is determined b

Question

The initial momentum of the steel ball at the bottom of the ramp is determined by letting a ball roll from a height, h above the ramp. As it rolls down the ramp, its speed increases. The speed at the bottom of the ramp can be determined by applying the principle of conservation of energy since there is very little energy lost due to rolling friction. At height, h, the total mechanical energy is the potential energy, mgh and at the bottom of the ramp, all the potential energy is converted into the translation (

Explanation / Answer

part A:   use Horizonatal velocity at the bottom Vb = sqrt(7/10) gh

Vb = sqrt(7* 9.81 * 0.1611)

Vb = 3.326 m/s
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Momentum P = mv

P = 0.0253 * 3.326

P =0.0841 Kgm/s

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time t = sqrt(2H/g)

t = sqrt(2* 0.259/9.81)

t = 0.229 secs

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Xo = ux*t

Xo = 3.326 * 0.229

xo = 0.761 m   or 76.16 cm

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