A length of wire is formed into a coil of 21.00 square loops with the sides of t

Question

A length of wire is formed into a coil of 21.00 square loops with the sides of the square being 2.50 cm long. The loop is placed in a uniform 480.0 mT magnetic field and subjected to a  current of 71.0 mA.

a) What torque in N-m will be exerted on the coil when the magnetic field is parallel to the plane of the coil?

b) What torque in N-m will be exerted on the coil when the magnetic field is perpendicular to the plane of the coil?

c) What torque in N-m will be exerted on the coil when the magnetic field makes an angle of 60.0

Explanation / Answer

A. torque doe a loop is T = NIAB sin theta

so

a. when B is parallel to the plane of coil, theta = 90 deg

so T    =   21 *0.025*0.025 * 0.48 *0.071 * sin 90

T = 4.474 *10^-4 Nm

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when B is per[endicular , theta = 0 deg

as sin 0 = 0

Torque T = 0

-----------------------

when B is at 60 deg, anglre made is 30 deg

so

so T    =   21 *0.025*0.025 * 0.48 *0.071 * sin 30

T = 2.23 *10^-4 Nm

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