1. Three electric charges are arranged as follows: +2.00 nC at (0,0), +2.00 nC a
ID: 1315703 • Letter: 1
Question
1. Three electric charges are arranged as follows: +2.00 nC at (0,0), +2.00 nC at (0, 0.500 m) and -2.00 nC at (0.500 m, 0.500 m). Determine the electric field at the position (0.500 m, 0).
2. A 25.0 ?F and a 40.0 ?F capacitor are connected in parallel across a 50.0 V battery. They are then carefully removed from the battery and each other and reconnected with unlike terminals together. Determine:
a. the voltage across each capacitor, and
b. the charge on each capacitor.
c. what is the stored energy difference, if any, between the initial
conditions and the final conditions?
3. At a certain distance from a point charge the electric field has a magnitude of 1.00 kV/m and the potential is +500. V. Determine: a. the magnitude and sign of the charge, and b. the distance away from the charge where the measurements were recorded.
4.
Alpha particles with an initial speed of 1.75x107 m/s are fired at a thin sheet of gold from a distance of 10.0 cm. (Alpha particles are obtained from certain radioactive decays. They have a charge of +2e and a mass of 6.64x10-27 kg. How close can the alpha particles get to a gold nucleus ( charge = +79e), assuming the nucleus remains stationary?
electronic charge, |e|, 1.602x10-19 C Coulomb constant 8.988x109 N
Explanation / Answer
electric field due to -ve chareg is attractive, due to +ve chareg is repulsive
angle between electric field due chareg at origin and at (0.5,0.5) is 90
net E=21/2E1
E1=kq/0.52
this E makes angle of 90 with electric field due to-ve chareg
net Enet=21/2E
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.