The masses attached to each side of an ideal Atwood\'s machine consist of a stac
ID: 1315360 • Letter: T
Question
The masses attached to each side of an ideal Atwood's machine consist of a stack of five washers, each of mass m, as shown in the figure below. The tension in the light string Is To. When one of the washers is removed from the left side, the remaining washers accelerate and the tension decreases by 0.300 N. (Assume that the pulley is massless and frictionless.) (a) Find m. g (b) Find the new tension and the acceleration of each mass when a second washer is removed from the left side. new acceleration m/s^2 new tension NExplanation / Answer
(a):
T0 = 5mg N
let T1 be the Tension after washer is removed from left
therefore,
T1 = 4mg + 4 ma
T1 + 5ma = 5mg
therefore
4mg + 4ma + 5ma = 5mg
a = g/9
therefore
T1 = (40/9)mg
according to ques.
T0 - T1 = (3/10)
so,
5mg + (40/9)mg = (3/10)
m = 27 / (50*g)
m = 0.0551 kg
(b):
let T2 be tension when 2'nd washer is removed from left
T2 = 3mg + 3ma
T2 + 5ma = 5mg
therefore,
a = g/4 = 2.45 m/s^2
so,
T2 = 4mg = 4*0.0551*9.8 = 2.1599 N
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