The two wires shown in the figure below carry currents of I = 4.62 A in opposite

Question

The two wires shown in the figure below carry currents of I = 4.62 A in opposite directions and are separated by d0 = 9.63 cm.

1. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction.

2. Calculate the net magnetic field at point P1 - that is, d1 = 8.82 cm to the right of the wire on the right.

3. Calculate the net magnetic field at point P2 - that is, d2 = 21.1 cm to the left of the wire on the left.

Explanation / Answer

Part 1)

In the middle the fields will add

The general formula is B = uI/2pir for each wire

Son in the middle, B = 2uI/2pir

B = 2(4pi X 10-7)(4.62)/2pi(.04815)

B = 3.84 X 10-5 T

Part 2)

The fields will subtract

B = (4pi X 10-7)(4.62)/2pi(.0882) - (4pi X 10-7)(4.62)/2pi(.1845)

B = 5.46 X 10-6 T

Part 3)

B = (4pi X 10-7)(4.62)/2pi(.221) - (4pi X 10-7)(4.62)/2pi(.3173)

B = 1.27 X 10-6 T

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