a)True False N NE E SE S SW W NW The direction of the force on a small (-) charg
ID: 1314106 • Letter: A
Question
a)True False N NE E SE S SW W NW The direction of the force on a small (-) charge at 5 is ....
b)True False N NE E SE S SW W NW The magnitude of the E-field at 2 is very small (~ zero).
c)True False N NE E SE S SW W NW The x-component of the E-field at 3 is positive.
d)True False N NE E SE S SW W NW The direction of the E-field at 6 is ....
e)True False N NE E SE S SW W NW The magnitude of the E-field at 3 is greater than that at 4
f)True False N NE E SE S SW W NW The direction of the force on a small (+) charge at 9 is ....
g)True False N NE E SE S SW W NW The y-component of the E-field at 9 is zero.
2)Calculate the work which would be required to move a charge Q = 68.1 nC from '1' to '6'.
Careful with signs: of the charge, of the change in PE.Explanation / Answer
since electric potential decreases in direction of electric field, electric field is from square to rod
1)True
2)West
3)North-West
4)True
5)True
6)True
7)North
Work = q*dv = q*(-2000-(-4000)) = 1.406*10^-4 J
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