Why .should the graph of velocity versus time for the falling plummet be a strai
ID: 1313982 • Letter: W
Question
Why .should the graph of velocity versus time for the falling plummet be a straight line? Why should the graph of total distance traveled versus time for the falling plummet not be a straight line? During any particular time interval of 1/60th of a second, was the velocity constant? When was the instantaneous velocity greater: at the beginning of the 1/60th second time interval or at the end of the 1/60th second time interval? When you plotted the graph of velocity versus time, the instantaneous velocities were plotted versus what times: the time at the beginning of each time interval, the mid-time of each time interval, or the time at the end of each time interval? Why? When you plotted the graph of measured distance versus time, the distances were plotted versus what times , the time at the beginning of each time interval, the mid-time of each time interval, or the time at the end of each time interval? Why? The velocity of the falling plummet was not equal to zero at time zero on your graph. That is, the v vs. t graph did not go through the origin. From the graph that you plotted, what was the velocity at time 0? Record here the value of the velocity at time 0 from the y-intercept in the equation for the straight line on the v vs. t graph generated using Excel. If the plummet fell from rest, why is the velocity not equal to zero at time zero on your graph? (Think about how you examined your data or look at your waxed-coated paper tape in answering this question.)Explanation / Answer
1.
The slope of graph represents dv/dt =a , acceleration. As the acceleration of falling plummet is constant.So slope is constant and is a straight line.
Slope in distance time graph represent ds/dt = v= velocity which is not constant during the motion. Hence, graph is not a straight line.
2.
No, velocity is incresing.
Instantaneous velocity is greater at the end if interval of 1/60 th of a second.
In velocity versus time graph we take the time at the mid of interval to get most appropriate values.
In distance versus time graph we take time at the beggining of interval.
3.
Putting x = 0 in equation
We get v = 176.69 m/s
Velocity is not zero at t=0 because we started taking the readings at a later time when plummet gained velocity.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.