A 1.150 kg air-track glider is attached to each end of the track by two coil spr
ID: 1312968 • Letter: A
Question
A 1.150 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.130 m.
A) Find the effective spring constant of the system.
B) The glider is now released from rest at x= 0.130 m. Find the maximum x-acceleration of the glider.
C) Find the x-coordinate of the glider at time t= 0.630T, where T is the period of the oscillation.
D) Find the kinetic energy of the glider at x=0.00 m.
PLEASE SHOW ALL WORK SO I UNDERSTAND HOW TO FIND THE ANSWER! tHANK YOU!
Explanation / Answer
A 1.150 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.130 m.
Force = -k * (distance stretched)
0.700 = -k *0.130
k = 5.38 N/m
As the glider is moved 0.130 m, the force increases from 0 N to 0.700 N
When the glider is released, the force decrease from 0.700 N to 0 N as it moves back to the original position. Then increases from 0 N to 0.700 N, in the opposite direction, as the glider slides to the farthest position.
Max acceleration = max force
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