An object of mass m = 0.455 kg is suspended from the ceiling of an accelerating

Question

An object of mass m = 0.455 kg is suspended from the ceiling of an accelerating truck as in the figure below. Take a = 2.30 m/s2. If the horizontal acceleration were zero, then the angle would be 0 degree , and if a = g, then the angle would be 45 degree. Since the acceleration is 2.30 m/s2, a reasonable estimate of the angle would be somewhat smaller than 45 degree. Similarly, an estimate of the tension in the string would be slightly greater than the weight of the object. We will apply Newton's secand law to the hanging object, modeling the object as a particle under a net force. The only forces acting on the suspended object are the force of gravity Fg = mg down and the force of tension T forward and upward, as shown in the free-body diagram. Note that the angle 6 is between T and the y axis, so T cos 6 is the y component. We assume that the object is not swinging like a pendulum, so that 6 is constant and the object moves with the same acceleration as the truck. Applying Newton's secand law in the x and y directions,

Explanation / Answer

a) first box - 2.3

second box - 9.8

third box - 0.2346

fourth box - 0.2346

fifth box - 13.20

b) tension = 4.58 N

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