A positive charge q1 is located 3.50 m to the left of a negative charge q2. The

Question

A positive charge q1 is located 3.50 m to the left of a negative charge q2. The charges have different magnitudes. On the line through the charges, the net electric field is zero at a spot 1.00 m to the right of the negative charge. On this line there are also two spots where the total electric potential is zero. Locate these two spots relative to the negative charge.

x=_______ m to the right of the negative charge

x=_______ m to the left of the negative charge

please explain thoroughly to recieve points!

Explanation / Answer

electric field due to positive charge will be towards right, and negative charge will be towards left , since it is given that the point is at right of negative charge.

at that point E=0:

positive charge = q1, negative charge = q2.

E= q/4piE0r2

the point is at a distance of 1 mts from q2

q1/(1+3.5)2 = - q2/12  

q1 = - 20.25q2.

potential at any point being at a distance of r from negative charge q2 on right side can be given as =

q1/4piE0(r+3.5) + q2 / 4piE0r

r=0.182 mts.

if the point is located in between the points, then

let the point is at a distance of r mts from q2:

q1/4piE0(3.5-r) +q2/4piE0r =0

r= 0.1647 mts left to negative charge, q2

point left toboth charges having 0 potential is not possible, since r becomes a negative value which never exist

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