Two blocks are free to slide along the frictionless wooden track shown below. Th

Question

Two blocks are free to slide along the frictionless wooden track shown below. The block of mass m1 = 4.94 kg is released from the position shown, at height h = 5.00 m above the flat part of the track. Protruding from its front end is the north pole of a strong magnet, which repels the north pole of an identical magnet embedded in the back end of the block of mass m2 = 10.1 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision.

Explanation / Answer

Sinece in elastic collision momemtum n kinetic energy both are conserved

And velocity is directly proportional to distance

Since

M1v1=m2v2

So we can write that

M1h1=m2h2

4.94*5= 10.1*h2

H2=4.94*5/ 10.1=2.47m

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