Easy Physics Question: Momentum elastic collision I just need help making sure i

Question

Easy Physics Question: Momentum elastic collision

I just need help making sure i did this right and how to finish the answer correctly.

Say two blocks are thrown at each other...

Block A with MV=(10kg)(15m/s) travels north ^

Block B with MV=(20kg)(10m/s) travels west >

They collied.

I want to find the change in distance after collision and how long it took to come to a stop.

I know Px= (20)(10) = 200

Py = (10)(15) = 150

P total = Px^2 + Py^2 = P^2 ===> 250

I know these vectors make a right triangle with and angle of 36.9

1)height = (.5*mv^2=mgh) or 2)h=((V0^2*sin(angle)^2) / 2g)

question: do i use the 2nd h= equation for each block? to see how high they went from origin?

Say i find the 2 h's (y) for block a and b, how do i find each change in distance and each time to reach a stop?

i know J=F*time = P=MVfinal-MVinitial

and then

change in x = vot+.5*at^2

a= F/m

250/20=aBblock

250/10=aAblock

right? :s please help i'm kinda confused

I just dont know how to find these values for the 2 blocks in elastic collision.

Explanation / Answer

for calculation of height you can use the 1st method as you can always equate the final and initial energy in elastic collison (.5*mv^2=mgh) and v here will be velocity of cubes after collision

and for time also you are calculating the right method

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