The magnetic flux phi B = B. Area can be written out using the magnetic field of

Question

The magnetic flux phi B = B. Area can be written out using the magnetic field of the solenoid and the cross sectional area. Take the solenoid as having a radius r, and n turns per cm and write the expressions for B, Area and phi B. B = Area = phi B = Now we will assume that delta phi / beta t is caused by a changing current with delta l/ delta t. For delta phi /delta t, replace the current I in phi B with delta l/delta t. The number of turns N in the solenoid is equal to the turns per length (N/L) times the length of the solenoid l. Make the substitutions and gather terms to solve for L . What would change in the expression if there were a material other than air (vacuum) inside the solenoid? Identify the geometric terms and the material properties in the expression for L

Explanation / Answer

B=(permeability of free space)(Number of turns/Length)Current
Area= pi*(radius)^2
Magnetic flux=magnetic field*Area

Magentic Field inside a Solenoid is given by:-

B=(?0NI/l)

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