A physics book slides off a horizontal tabletop with a speed of 3.60m/s . It str

Question

A physics book slides off a horizontal tabletop with a speed of 3.60m/s . It strikes the floor in 0.350s . Ignore air resistance.

A) Find the height of the tabletop above the floor.

B) Find the horizontal distance from the edge of the table to the point where the book strikes the floor.

C) Find the horizontal component of the book's velocity, just before the book reaches the floor.

D) Find the vertical component of the book's velocity just before the book reaches the floor.

E) Find the magnitude of book's velocity, just before the book reaches the floor.

F) Find the direction of book's velocity, just before the book reaches the floor.

Explanation / Answer

For the first part, assuming there is no initial vertical velocity (which in this case, there is not), T = sq. rt. (2h/g) where T is time, h is the vertical height that it falls, and g is the acceleration due to gravity. 0.350 = sq. rt. (2h/9.8) .1223 = 2h/9.8 2h = 1.2005 h = about .6 meters d = v t where d = distance, v = velocity, and t = time. d= (1.10)(0.350) = 0.385 meters

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