In the figure a compass sits 1.1cm above a wire in a circuit containing a 1.0F c

Question

In the figure a compass sits 1.1cm above a wire in a circuit containing a 1.0F capacitor charged to 4.8V , a 1.0? resistor, and an open switch. The compass is lined up with the earth's magnetic field. The switch is closed, so that there is a current in the circuit, and the switch remains closed until the capacitor has completely discharged.

Part A asked for the magnitude of the magnetic field due to the current in the wire right after the switch is closed. The answer is 8.7x10-5 T.

How does this compare with the magnitude of the field of the earth (Bearth ? 5

Explanation / Answer

current=V/R

=4.8/1

=4.8 A

so B=uo*i/(2pi*d)

=2*10^-7*4.8/(1.1*10^-2)

=8.73*10^-5 T

so comparison=8.73*100/5

=176.4 %

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