2). A tank of water sits at the edge of a table of height 1.1 m. The tank spring

Question

2). A tank of water sits at the edge of a table of height 1.1 m. The tank springs a very small leak at its base, and water sprays out a distance of 0.9 m from the edge of the table. What is the water level h in the tank? (Assume the tank is open to the air at the top.) In CM please.

3). When a person is given intravenous fluid, the bag containing the fluid is typically held about 0.8 m above the person's body. If the pressure in this fluid is just barely able to push the fluid into the person, what is the pressure in the person's blood? (The density of the intravenous fluid is approximately that of water.)

= Pa.

4). The pressure in the atmosphere is not constant, but fluctuates as the weather changes. If the pressure outside a window drops by 7% while the pressure inside does not change, what is the force on the window? Assume the area of the window is 2.1 m2. (The positive direction is toward the inside of the window. Indicate the direction with the sign of your answer. Assume that the initial pressure inside and outside the window is initially 1 atm.) In N

Please Help!! Can you show work too?!

Explanation / Answer

Number 1)

We need the velocity

V = Av

2.3 X 10-7 = (pi)(.0024)2(v)

v = .01271 m/s

P = .5pv2

P = (.5)(1000)(.01271)2

P = .0808 Pa (8.08 X 10-2 Pa)

Number 2

Start with d = vot + .5at2 in the y direction to find the time to drop to the floor.

1.1 = 0 + .5(9.8)(t2)

t = .4738 s

Then in the x, d = vt

.9 = v(.4738)

v = 1.90 m/s

Finally apply pgh = .5pv2

(9.8)(h) = .5(1.90)2

.184 m which is 18.4 cm

Number 3)

P = Patm + pgh =

P = (1.013 X 105) + (1000)(9.8)(0.8)

P = 1.09 X 105 Pa

Number 4)

The pressure difference is .07(1.013 X 105) = 7091 Pa

P = F/A

F = PA = (7091)(2.1) = 14891 N

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