A bullet is shot to a target. At the instant the bullet leaves the muzzel of the
ID: 1305133 • Letter: A
Question
A bullet is shot to a target. At the instant the bullet leaves the muzzel of the gun, the target starts dropping from rest from the ceiling. When the bullet hits the target, the target has dropped 1.800 m. The muzzel velocity of the bullet is 16.000 m/s and the initial velocity vector makes an angle of 50 degrees with the horizontal. Neglect friction and air resistance.
The vertical component of the initial speed of the bullet is _________.
The horizontal component of the initial speed of the bullet it __________.
The elapsed time from the instant the bullet left the muzzel until it hit the target is ___________.
At the moment when the bullet hit the target, its vertical speed is ____________.
At the moment when the bullet hit the target, its horizontal speed is __________.
Explanation / Answer
16,000sin 50 12,256.71 m/s
16,000 cos 50= 10,284.60 m/s
1.8= 4.9t^2= 0.606 sec
12,256,71- .606*9.8 = 12,250.77m/s
10,284.60 m/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.