1. A ray of light passes from water to glass at an angle of incidence of 50degre

Question

1. A ray of light passes from water to glass at an angle of incidence of 50degrees. Find the angle of refraction.

2. A ray of light in air makes an angle of incidence of 35degrees as it enters an unknown liquid. The refracted ray in the fluid is measured to be 22.5degrees. Find the index of refraction of the unknown liquid. What substance might it be?

3. If a ray of light of 480nm wavelength in air enters into water, what is the wavelength of the light in the water? Is this light visible?

4. A rock splits at the bottom of a 3.5m deep pool. What is the apparant depth?

5. Find the critical angle of refraction for a ray of light passing from glycerine (n = 1.47) into air.

Explanation / Answer

Number 1)

Apply Snells's Law

n1sin(i) = n2(sin r)

I will use index of refraction of 1.33 for water and 1.52 for glass. You did not include the values your book uses so I have to use mine. If this answer is off, please comment below and I can help further. I know you said you are new, so remember for the future to provide any constants needed from your materials because different books use different values...

(1.33)(sin 50) = (1.52)(sin r)

r = 42o (This answer could also be 37.9o using a different type of glass)

Number 2)

Also Snell's Law

(1)(sin 35) = n(sin 22.5)

n = 1.50 (Probably Benzene, or maybe crown Glass, but again, that depends on a table from your book)

Number 3)

Apply (wavelength)(n) = wavelength(n)

480(1) = wavelength(1.33)

wavelength = 360.9 nm

Here is number 5 also, since it is easy enough

Number 5)

sin (ic) = n2/n1

sin(ic) = 1/1.47

ic = 42.9o

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