Two speeding lead bullets, one of mass 14.0 g moving to the right at 305 m/s and
ID: 1304827 • Letter: T
Question
Two speeding lead bullets, one of mass 14.0 g moving to the right at 305 m/s and one of mass 7.50 g moving to the left at 375 m/s, collide head-on, and all the material sticks together. Both bullets are originally at temperature 30.0 degree C. Assume the change in kinetic energy of the system appears entirely as increased internal energy. We would like to determine the temperature and phase of the bullets after the collision. (Lead has a specific heat of 128 J/(kg K), a melting point of 327.3 degree C, and a latent heat of fusion of 2.45 x io4 J/kg.) What analysis model is appropriate for the system of two bullets for the time interval from before to after the collision? nonisolated system (momentum) particle in equilibrium isolated system (momentum) particle under a net force From the model, what is the speed of the combined bullets after the collision? How much of the initial kinetic energy has transformed to internal energy in the system after the collision? 1.13E3 Does all the lead melt due to the collision? What is the temperature of the combined bullets after the collision? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error, g Your response differs from the correct answer by more than 10%. Double check your calculations, g (f) What is the phase of the combined bullets after the collision? m.Explanation / Answer
so
Q = m c dT + mliquid L
1.13E3 = (14.0E-3+7.5E-3)*128*(327.3-30) + m*2.45E4
m liquid = 0.0127 kg = 12.7 g
so m solid = 14+7.5-12.7= 8.8 g
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