completes one revolution in 30 s what is the speed located ofa rider at Ulm m fr

Question

completes one revolution in 30 s what is the speed located ofa rider at Ulm m from the center of the merry-go-round? 19 a) 0.1 m/s b) 0.2 m/s c) 2 m/s d) 6 m/s e) 30 m/s 20, A0.50-kg mass is attached to the end of a 1.0-m string, The system is whirled in a horizontal circular path If the maximum tension that the string can withstand is 350 N. What is the maximum speed of the mass if the string is not to break? A) 700 m/s B) 26 m/s C) 19 m/s D) 13 m/s 21. A force F pushes a block along a horizontal surface against a force of friction Fr If the block undergoes a displacement s at constant velocity, the work done by the resultant force on the block is equal to the work done by the force of friction Fr b) is given by W's F s c) increases the kinetic energy of the block. d) increases the potential energy of the block. e) is zero. 22. A motorcycle of mass m starting from rest can attain a speed v after work W is performed by its engine. If the engine could perform work 4w then the final speed would be? A) 4 B) 2v C) 16v D) (2v)12 E) (4v) 23. The angle between the vector A i 2 j 3k and the x axis is approximately A) 17 B) 260 C) 37 D) 580 E) 750

Explanation / Answer

19) v = w r = 2 pi r/T

the distance got cut off but plut in for for and T

20)

T = mv^2/r

350 = 0.5*v^2/1

v = sqrt(700) = 26 m/s

so b)

21) W = dKE
since constant v, netWork = 0

so e)

22) W = dKE = 1/2 mv^2

so 4 W means 2 v

so b)

23) A*x = 1

but A*x = |a||x| cos theta

|A| = sqrt(1^2 + 2^2 + 3^2)

theta = arcos(1/ sqrt(1^2 + 2^2 + 3^2) ) = 75 so E)

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