2. A student builds the following circuit in a lab experiment, which she records
ID: 1303417 • Letter: 2
Question
2. A student builds the following circuit in a lab experiment, which she records and takes home to analyze.
She uses a voltmeter, that measures in volts, and an ammeter that measures in amps.
Both were correctly placed in her circuit. In her notes she wrote
x = 0.15 z = 0.3 but did not indicate volts or amps, or which meter was which.
The resistor on the left is 5 ohms, and so is the one on the right.
(A) Which was the ammeter? explain.
(B) What is the voltage difference across each resistor? Explain.
(C) What is the voltage of the battery? Explain.
3. The following questions refer to the figure below. At the start , the switch between points c and d is open as drawn on the figure. The battery is 5 V. At this time (switch open) the current measured at point a is 5 ma, and there is a 3 V difference between a and b. R2 is larger than R3.
(A) What is the current at point d?
(B) What is the voltage between points b and d?
(C) What is the voltage between points b and c?
(D) What is the effective resistance of the circuit?
(D) If the switch is closed, explain what happens to the current at point a. (You don
Explanation / Answer
1)
If the homes were wired in series, then if one of the homes face short circuit then all the houses would face power cut but it doesnt happen. So they must be connected in parallel.
2)
A)
An ammeter mus tbe connected in series. So ammeter must be x
and thus voltmeter must be z
B)
x = 0.15 A
z = 0.3 V
So, voltage across R1 (left resistor) = 5*x = 5*0.15 = 0.75 V
voltage across the right = 0.3 V
C)
total voltage of battery = 0.75+0.3 = 1.05 V
3)
A)current at d = same at a = 5mA
B) voltage between b and d = 5-3 = 2 V
C) voltage between b and c = 0 V <---- as c is not connected to the circuit
D) effective resitance = V/I = 5/(5m) = 5/0.005 = 1000 ohm
E) if switch is closed net resistance of circuit decreases, So, current at a increases <-------answer
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