1- A 5.7cm-thick layer of oil ( n =1.46) is sandwiched between a 1.0cm-thick she
ID: 1301730 • Letter: 1
Question
1- A 5.7cm-thick layer of oil (n=1.46) is sandwiched between a 1.0cm-thick sheet of glass and a 2.1cm-thick sheet of polystyrene plastic (n=1.59).
Part A
How long (in ns) does it take light incident perpendicular to the glass to pass through this 8.8cm-thick sandwich?
2-Two lasers are shining on a double slit, with slit separation
d. Laser 1 has a wavelength ofd/20, whereas laser 2 has a wavelength ofd/15
. The lasers produce separate interference patterns on a screen a distance 5.70m away from the slits.
PART A
What is the distance?ymax?minbetween the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum?
Express your answer in meters.
3- A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. There exist, however, certain conditions under which the range of vision is not so extended. For example, a nearsighted person cannot focus on objects farther than a certain point (the far point), while a farsighted person cannot focus on objects closer than a certain point (the near point). Note that even though the presence of a near point is common to everyone, a farsighted person has a near point that is much farther from the eye than the near point of a person with normal vision.
Both nearsightedness and farsightedness can be corrected with the use of glasses or contact lenses. In this case, the eye converges the light coming from the image formed by the corrective lens rather than from the object itself.
Part B
If a nearsighted person has a far pointdfthat is 3.50m
from the eye, what is the focal length f1 of the contact lenses that the person would need to see an object at infinity clearly?
Express your answer in meters.
Part D
If a farsighted person has a near point that is 0.600m
from the eye, what is the focal lengthf2
of the contact lenses that the person would need to be able to read a book held at 0.350m from the person's eyes?
Express your answer in meters.
1- A 5.7cm-thick layer of oil (n=1.46) is sandwiched between a 1.0cm-thick sheet of glass and a 2.1cm-thick sheet of polystyrene plastic (n=1.59).
Part A
How long (in ns) does it take light incident perpendicular to the glass to pass through this 8.8cm-thick sandwich?
2-Two lasers are shining on a double slit, with slit separation
d. Laser 1 has a wavelength ofd/20, whereas laser 2 has a wavelength ofd/15
. The lasers produce separate interference patterns on a screen a distance 5.70m away from the slits.
PART A
What is the distance?ymax?minbetween the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum?
Express your answer in meters.
3- A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. There exist, however, certain conditions under which the range of vision is not so extended. For example, a nearsighted person cannot focus on objects farther than a certain point (the far point), while a farsighted person cannot focus on objects closer than a certain point (the near point). Note that even though the presence of a near point is common to everyone, a farsighted person has a near point that is much farther from the eye than the near point of a person with normal vision.
Both nearsightedness and farsightedness can be corrected with the use of glasses or contact lenses. In this case, the eye converges the light coming from the image formed by the corrective lens rather than from the object itself.
Part B
If a nearsighted person has a far pointdfthat is 3.50m
from the eye, what is the focal length f1 of the contact lenses that the person would need to see an object at infinity clearly?
Express your answer in meters.
Part D
If a farsighted person has a near point that is 0.600m
from the eye, what is the focal lengthf2
of the contact lenses that the person would need to be able to read a book held at 0.350m from the person's eyes?
Express your answer in meters.
Explanation / Answer
1)
d = v * t
t = d/v
Take the distance (in m) and divide by the velocity of light (in m/sec). The velocity in each segment is (3 x 10^8 m/sec)/n where n = index of refraction.
2)
x(1) = 0.57 ( for the 2nd max )
x(2) = 2.5 *5.7 / 15 = 0.95 m ( for the 3rd in )
Separation = 0.38 m
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