http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/c30/fig30_47.gif Th

Question

http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/c30/fig30_47.gif

The figure shows two parallel loops of wire having a common axis. The smaller loop (radius r = 1.6 cm) is above the larger loop (radius R = 6.1 cm) by a distance x = 0.96 m. Consequently, the magnetic field due to the counterclockwise current i= 15 A in the larger loop is nearly constant throughout the smaller loop. Suppose that x is increasing at the constant ratedx/dt = v = 0.091 m/s. (a) Determine the magnetic flux through the area of the smaller loop. (b) Find the emf induced in the smaller loop.

Explanation / Answer

a)

The magnetic flux through the smaller loop is

?B = ??0ir2R2/2x3

      =?(4?*10-7Tm/A)(15A)(0.016m)2(0.061)2/2(0.96 m)3

     = 3.188*10-11 Wb

b)

The emf induced in the smaller loop is

? = -d?B/dt

= -(??0ir2R2/2)(-3/x4*dx/dt)

= 3??0ir2R2v/2x4

= 3?(4?*10-7Tm/A)(15A)(0.016m)2(0.061)2(0.091 m/s)/2(0.96 m)4

= 9.066*10-12 V

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.