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Two nested. ideal solenoids are aligned concentrically along the same axis The o

ID: 1300851 • Letter: T

Question

Two nested. ideal solenoids are aligned concentrically along the same axis The outer solenoid is connected to a variable current supply. and it initially carries a current I1 in its coils in the direction shown in its wires above. The inner solenoid's current I2 is initially zero. Assume that both solenoids have some small, but non - zero. resistance. Note: NOT all of the above values may he used in the following calculations You do NOT need to show your work for this question Be sure to include correct units and sig.figs.. Based on the direction of I1 at the instant shown above, what is the direction of the magnetic Held B, inside the outer (larger) solenoid's coils? to the right out of page toward top of page (o the left into the page toward bottom of page Suppose that I1 decreases linearly from 20.0 A to 10.0 A during a time period of 33 J ms. Ignoring the inner solenoid, what is the change in energy of the outer (larger) solenoid during this time period? (Recall: For an ideal straight solenoid. L = mu 0 N2A/l Now. including the inner solenoid...In which direction is the current l: induced in the inner (smaller) solenoid during this time period? In the same direction as the circulation of I1 in the opposite direction as the circulation of I1 Assuming that the outer (larger) solenoid is ideal, what is the strength of the total emf induced in the inner (smaller) solenoid during this time period?

Explanation / Answer

a) use right hand rule and get to the left
B)

b) E= 1/2 L I^2

so dE = 0.5*4*pi*10^(-7)*780^2*pi*4.0E-2^2/.55*(10^2-20^2)=-1.048 J

c) so therewill be less flux to the left so it will put its fieldtothe left as well
so same as I1 A)

d) emf = dflux/dt = N A dB/dt
but B = u0 N I/L

so emf = N A u0 N1 dI/dt/L1

= 250*pi*3.0E-2^2*4*pi*10^(-7)*780*(10/33.3E-3)/.55= 0.378 v

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