left end of a long glass rod, 10.0cm in diameter, has a convex hemispherical sur

Question

left end of a long glass rod, 10.0cm in diameter, has a convex hemispherical surface 5.00cm in radius. The refractive index of the glass is 1.60.

Part A

Determine the position sb of the image of an object placed in air on the axis of the rod infinitely far from the left end of the rod.

Express your answer in centimeters to three significant figures.

13.3

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Correct

Since the position is a positive number, the image is formed to the right of the surface and is a real image.

Part B

Determine the position sb of the image if an object is placed in air on the axis of the rod 13.0cm to the left of the end of the rod.

Express your answer in centimeters to three significant figures.

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Part C

Determine the position sb of the image if an object is placed in air on the axis of the rod 2.00cm from the left end of the rod.

Express your answer in centimeters to three significant figures.

I keep getting PART B wrong

left end of a long glass rod, 10.0cm in diameter, has a convex hemispherical surface 5.00cm in radius. The refractive index of the glass is 1.60.

Part A

Determine the position sb of the image of an object placed in air on the axis of the rod infinitely far from the left end of the rod.

Express your answer in centimeters to three significant figures.

sb =

13.3

cm

SubmitHintsMy AnswersGive UpReview Part

Correct

Since the position is a positive number, the image is formed to the right of the surface and is a real image.

Part B

Determine the position sb of the image if an object is placed in air on the axis of the rod 13.0cm to the left of the end of the rod.

Express your answer in centimeters to three significant figures.

sb = cm

SubmitMy AnswersGive Up

Incorrect; Try Again; 4 attempts remaining

Part C

Determine the position sb of the image if an object is placed in air on the axis of the rod 2.00cm from the left end of the rod.

Express your answer in centimeters to three significant figures.

sb = cm

Explanation / Answer

The experssion for the object and image distances for a refracting surface is given as

( n1 / So ) + (n2 / Sb) = [ (n2 -n1) / R ]

n1 is the refractive index of air n1 = 1 , n2 is refractive index of glass n2 = 1.6

S0 is objeect distance = 13 cm

R is radius of curvature R = 5 cm

( 1 / 13) + (1.6 / Sb) = [ ( 1.6 - 1) / 5 ]

Sb = 37.14 cm

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