Have the answer just need help working it out please. Question 2 2. A uniform 30

Question

Have the answer just need help working it out please. Question 2

2. A uniform 300-kg beam, 6.00 m long is freely pivoted at P, as shown in the figure. The beam is supported in a horizontal position by a light strut, 5.00 m long, which is freely pivoted at Q and is loosely pinned to the beam at R. A load of mass is suspended from the end of the beam at S. A maximum compression of 23,000 N in the strut is permitted, due to safety. The maximum mass M of the load is closest to A. 554 kg. B. 789 kg. C. 1020 kg. D. 1090 kg. F. 1320 kg.

Explanation / Answer

B. 789 kg

First find the angle the strut makes with the beam

sin theta =4/5           

theta = 53.1 degrees

torque upward from strut - torque down fromweight of beam - torque down from M = 0

23000 * 3 * sin 53.1   - 300 * 9.8 * 3   - M * 9.8 * 6   = 0

M =   789 kg

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