B. the loop is pushed to the right, out of the magnetic field c. the llop is pus

Question

B. the loop is pushed to the right, out of the magnetic field

c. the llop is pushed upward, toward the top of the page

d. the loop is pushed downward, toward the bottom of the page

e. the tension in the wires increases but the loop does not move

a conducting loop is halfway into a magnetic field. supposed the magnetic field begins to decrease rapidly in strength. what happens to the loop? A. the loop is pulled to the left, into the magnetic field. B. the loop is pushed to the right, out of the magnetic field c. the llop is pushed upward, toward the top of the page d. the loop is pushed downward, toward the bottom of the page e. the tension in the wires increases but the loop does not move

Explanation / Answer

The loop is pushed to the right, out of the magnetic field.

The first this is to draw a force diagram, and the induced current is going counter clockwise.
Using the formula
F=ILxB, the force must be perpendicular all around the loop. The upper and lower ends of the bar will have forces that cancel out, however the only force left is on the left. Since L is pointing in the negative(because it follows the same direction of induced current) y-direction and the B-field points into the page, use the right hand rule and the force ends up pointing towards the right.

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.