As shown in the figure (Figure 1) , a layer of water covers a slab of material X

Q: As shown in the figure (Figure 1) , a layer of water covers a slab of material X

from snells law x*sin(90-67.14) = 1.31*sin47.18 x = 2.4 7 B) nwater*sin47.18 = nair*sinr 1.31*sin47.18 = 1*sinr r = 73.9 C) sin C = nwater/x sinC = 1.31/2.47 C = 32.03 D) v = c/x = 3e8/2.47 = 1.21*10^8 m/s

ID: 1298536 • Letter: A

Question

As shown in the figure (Figure 1) , a layer of water covers a slab of material X in a beaker. A ray of light traveling upwards follows the path indicated. Assume that?1 is a1 = 47.18? and that ?2 is a2 = 67.14?.

A. Find index of refraction of meterial X, Use 1.31 for the index of refraction of water.

2.47 (correct)

B. Find the angle the light makes with the normal in the air. 73.9 (correct)

What is the critical angle for substance X if the light was leaving it and going out to air?

What is the speed of light in substance X?

Explanation / Answer

from snells law

x*sin(90-67.14) = 1.31*sin47.18

x = 2.4 7

nwater*sin47.18 = nair*sinr

1.31*sin47.18 = 1*sinr

r = 73.9

sin C = nwater/x

sinC = 1.31/2.47

C = 32.03

v = c/x = 3e8/2.47 = 1.21*10^8 m/s

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As shown in the figure (Figure 1) , a layer of water covers a slab of material X

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