They want the smallest visible wavelength (450 nm) to appear at an angular posit

Question

They want the smallest visible wavelength (450 nm) to appear at an angular position of 10 degrees. How far apart must the slits in the grating be? How many slits/mm is this?
The longest visible wavelength is about 670 nm. At what angle will this light appear?
What is the longest wavelength that could be seen with this grating? They want the smallest visible wavelength (450 nm) to appear at an angular position of 10 degrees. How far apart must the slits in the grating be? How many slits/mm is this?
The longest visible wavelength is about 670 nm. At what angle will this light appear?
What is the longest wavelength that could be seen with this grating?
The longest visible wavelength is about 670 nm. At what angle will this light appear?
What is the longest wavelength that could be seen with this grating?

Explanation / Answer

From the diffraction formual

d sin theta = m L

d = mL/sin theta = 1(450 nm)/ sin 10 = 2.6 * 10^-6 m

N = 1/d = 384.6 lines/mm

if L =670 nm

theat = sin^-1( mL/d) = sin^-1 ( 1(670 nm/2.6 * 10^-6 m) = 14.93

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