1. System = Two atoms bound together in a molecule and a single atom. These coll
ID: 1296814 • Letter: 1
Question
1. System = Two atoms bound together in a molecule and a single atom. These collide with each other but the state of the molecule is not changed (AB + C right arrow AB + C). Consider the time from a bit before the collision to a bit after. 2. System = same. But this time when they collide, the two atoms previously bound are broken apart (AB + C right arrow A + B + C). Consider the time from a bit before the collision (when it looks something like the picture in 1) to a bit after (when it looks something like the picture at the right). For the two systems below, ignore the effects of gravity. . Identify whether the objects in your system can be considered to conserve mechanical energy for the time interval described. . If mechanical energy of the system is NOT conserved, indicate whether the mechanical energy has increased or decreased and where (if it has increased) it came from, and where (if it decreased) it has gone (into what objects and forms).Explanation / Answer
Answer 1:
In the first case, a molecule AB and atom C collide, but the state of the molecules do not change.
AB + C ---> AB + C
Let initial Kinetic Energy of AB be KAB and C be KC
Final values be KAB' and KC'
Similarly potentail energy values be PAB, PC and PAB' , PC'
Kinetic energy arises due to motion and rotation (in case of AB) and potential energy arises due to intermolecular forces.
By law of conservation of energy:
Incase of no energy loss:
sum of initial KE + PE = final value is the required condition
KAB + KC + PAB + PC = KAB' + KC' + PAB' + PC'
Incase there is energy loss,
Sum of initial KE + PE = final sum + loss value
KAB + KC + PAB + PC = KAB' + KC' + PAB' + PC' + loss
The loss can be transfered into:
1. Light energy
2. Heat energy
3. Sound energy
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Answer 2)
In this case AB + C ---> A + B + C
By law of conservation of energy:
Incase of no energy loss:
sum of initial KE + PE = final value is the required condition
KAB + KC + PAB + PC = KA + KC' + PA + PC' + KB + PB
Incase there is energy loss,
Sum of initial KE + PE = final sum + loss value
KAB + KC + PAB + PC = KA + KC' + PA + PC' + KB + PB + loss
The loss can be transfered into:
1. Light energy
2. Heat energy
3. Sound energy
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