014 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with
ID: 1295823 • Letter: 0
Question
014 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with focal length 5.4 m. Another convex lens is placed 6.6 m behind the first lens with a focal length 5.2 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer. At what distance is the first image from the first lens? Answer in units of m 015 (part 2 of 4) 10.0 points What is the magnification of the first image? 016 (part 3 of 4) 10.0 points At what distance is the second image from the second lens? Answer in units of m 017 (part 4 of 4) 10.0 points What is the magnification of the final image, when compared to the initial object?Explanation / Answer
u1 = 10 m (object distance)
f1 = 5.4 m
let v1 is the image distance for the first lense.
we know,
1/u1 + 1/v1 = 1/f1
1v1 = 1/f1 - 1/u1
1/v1 = 1/5.4 - 1/10
v1 = 11.74 <<<<<<---------Answer
m1 = -v1/u1
= -11.74/5.4
= -2.174 <<<<<<---------Answer
u2 = 6.6-11.74 = -5.14 (object disatnce for the second lense)
now use,
1/u2 + 1/v2 = 1/f2
1v2 = 1/f2 - 1/u2
1/v2 = 1/5.2 + 1/5.14
v2 = 2.58 (from second lense) <<<<<<---------Answer
m2 = -v2/u2
= -2.58/(-5.14)
= 0.5
overall magnifiction, M = m1*m2
= -2.174*0.5
= -1.365 <<<<<<---------Answer
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