(1) A comet has a very elliptical orbit with a period of 117.2 y. If the closest
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Question
(1) A comet has a very elliptical orbit with a period of 117.2 y. If the closest approach of the comet to the Sun is 0.09 AU, what is its greatest distance from the Sun? _____AU
(a) What is the gravitational force on the satellite?
N
(b) What is the speed of the satellite?
km/s
(c) What is the period of the satellite?
h
Explanation / Answer
Kepler's law states that the period squared (t) is proportional to the semi major axis cubed (r)
You don't need to use that formula, only the ratio t^2/r^3 is a constant.
so :
1^2/1^3 (for earth) = 117.2^2/r^3
r^3 = 117.2^2
r = 23.9488
= 23.95 AU
2. A satellite with a mass of 310 kg moves in a circular orbit 8.00 107 m above the Earth's surface.
(a) What is the gravitational force on the satellite?
Fg= [(6.67x 10^-11)(330)(5.98 x 10^24)] divided by
(5*10^7m)^2
Fg= you solved it. Fg= mv^2/r, radius 6400 miles?
(b) What is the speed of the satellite? in km/s
v= sqrt (2gh)
v= you solved it.
(c) What is the period of the satellite? in h
t= 2d/ g.
t= you solve it.
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