A 0.40-kg iron horseshoe, just forged and very hot( Figure 1 ) , is dropped into

Question

A 0.40-kg iron horseshoe, just forged and very hot(Figure 1) , is dropped into 1.35L of water in a0.25-kg iron pot initially at 20.0?C. The value of specific heat for iron is 450 J/kg?C? , and for water is4186 J/kg?C? .

Part A

If the final equilibrium temperature is 25.0 ?C, Determine the initial temperature of the hot horseshoe.

A 0.40-kg iron horseshoe, just forged and very hot(Figure 1) , is dropped into 1.35L of water in a0.25-kg iron pot initially at 20.0?C. The value of specific heat for iron is 450 J/kg?C? , and for water is4186 J/kg?C? .

Part A

If the final equilibrium temperature is 25.0 ?C, Determine the initial temperature of the hot horseshoe.

Explanation / Answer

The equillibrium condition is

m_iron c_iron ( T_iron - T) = m_w c_w( T - T_w )+ m_pot c_iron ( 25 - 20 )

(0.4 kg ) ( 450 J / kg . oC ) ( T_ iron - 25 ) = ( 1.35 kg )( 4186 J /kg .oC ) ( 25 - 20 ) + (0.4 kg ) ( 450 J / kg . oC ) ( 5 )

   T_iron = 186.975 oC

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