A 1.09 kg block slides on a frictionless, horizontal surface with an speed of 1.
ID: 1292795 • Letter: A
Question
A 1.09 kg block slides on a frictionless, horizontal surface with an speed of 1.49 m/sec. The block encounters an unstretched spring with a spring constant of 295 N/m.
1) What is the initial kinetic energy of the block before it hits the spring?
KE0 =
2) What is the potential energy of the mass and spring system when the spring is at its point of maximum compression?
Umax =
3)
How far is the spring compress before the block comes to rest?
A =
4) If the mass and block were to oscillate, what would be the period of the oscillation?
T =
5) How long is the block in contact with the spring before it comes to rest?
t =
A 1.09 kg block slides on a frictionless, horizontal surface with an speed of 1.49 m/sec. The block encounters an unstretched spring with a spring constant of 295 N/m. 1) What is the initial kinetic energy of the block before it hits the spring? KE0 = 2) What is the potential energy of the mass and spring system when the spring is at its point of maximum compression? Umax = 3) How far is the spring compress before the block comes to rest? A = 4) If the mass and block were to oscillate, what would be the period of the oscillation? T = 5) How long is the block in contact with the spring before it comes to rest? t =Explanation / Answer
1) KE0 = mu^2 /2 = 1.09 x 1.49^2 /2 = 1.209 J
2) P.E. = KE0 = 1.209 J ( from energy conservation)
3) P.E = kx^2 /2 =
1.209 J= 295x^2/2=
x = sqrt(2.48 / 295)
x = 0.09169m
4) T = 2pi x sqrt(m/k) = 2 x pi s1rt(1.09 /295) = 0.381 sec
5) T = 4t
t = 0.381 sec/4 = 0.09525 sec
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