A group of students, performing the same \"Uniform Circular Motion\" experiment

Question

A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results. For this table, r is the distance from the center of rotation to the radius indicator (i.e., the post that marks the position of the center of the bob during rotation), mh is the total hanging mass (including the hanger), and t is the time required for 50 complete rotations. all calculations needed to compute the acceleration, a, for each trial.  a graph of mhg vs ac. mass of the bob (slope of the line) =

r(m)

Mh(kg)

t(s)

.1825

.08215

90.88

.2430

.11966

82.11

.2610

.13082

81.39

.2980

.15376

85.22

.3425

.18135

79.19

r(m)

Mh(kg)

t(s)

.1825

.08215

90.88

.2430

.11966

82.11

.2610

.13082

81.39

.2980

.15376

85.22

.3425

.18135

79.19

Explanation / Answer

0.2274 kg

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