A 0.18 m radius pulley is free to rotate about a horizontal axis. A 4.2 kg mass

Question

A 0.18 m radius pulley is free to rotate about a horizontal axis. A 4.2 kg mass and an 8.0 kg mass are attached by a massless string, which is hung over the pulley. If the string does not slip, calculate the magnitude of the net torque on the pulley about its rotational axis. A 0.18 m radius pulley is free to rotate about a horizontal axis. A 4.2 kg mass and an 8.0 kg mass are attached by a massless string, which is hung over the pulley. If the string does not slip, calculate the magnitude of the net torque on the pulley about its rotational axis.

Explanation / Answer

The moment of the force 8g about the center of the pulley is 8g* 0.18. in its direction
The moment of the force 4.2 g about the center of the pulley is 4.2g* 0.18. in the opposite direction.
The net moment is (8-4.2)*9.8* 0.18 = 6.7032 in the direction of 8g force.

Answer = 6.7 Nm.

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