In a horizontal spring-mass configuration, the position of the 0.63 kg mass is d

Question

In a horizontal spring-mass configuration, the position of the 0.63 kg mass is described by [x = (0.37 m) sin(2.73t)]

a) What is in meters the amplitude of these oscillations?

b) What is in m/s the maximum speed of the mass under these conditions?

c) What is in Joules the spring potential energy stored in this system when the spring is stretched at a maximum?

d) What is in Joules the kinetic energy of the mass when the spring is not stretched?

e) What is in Joules the kinetic energy of the mass when the spring is stretched by 0.06 m?

Explanation / Answer

x = 0.37 *sin2.73 *t

V = 0.37 *2.73 *cos2.73t

A. Vmax = 0.37 *2.73

= 1.01 m/s

B. energy = 1/2 *0.63 *v^2

   = 0.321 J

C. same as above = 0.31 J

D. 0.321 = 1/2 *4.689 *0.06^2 + K.E

K.E = 0.313 J

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