0.0025mol of gas follows the hyperbolic trajectory shown in ( Figure 1 ) . A) Wh

Question

0.0025mol of gas follows the hyperbolic trajectory shown in (Figure 1) .

A) What type of process is this? Isobaric or Isothermal or Isochoric?

B) What is the initial temperature? (in Celcius)

C) What is the final temperature? (in Celcius)

D) What is the final volume? (choose units)

0.0025mol of gas follows the hyperbolic trajectory shown in (Figure 1) . A) What type of process is this? Isobaric or Isothermal or Isochoric? B) What is the initial temperature? (in Celcius) C) What is the final temperature? (in Celcius) D) What is the final volume? (choose units)

Explanation / Answer

1)PV = constant is isothermal process

2) Initial temperature = (P*V)/(n*R) = (3*0.1)/(0.0025*0.0821) = 1461.63 K

3) At constant temperature, P1V1 = P2V2

or, 3*0.1 = 1*Vf

or, Vf = 0.3 litres = 300 cm3

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