The Bohr model of the hydrogen atom pictures the electron as a tiny particle mov

Question

The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the n=1 orbit the distance from the proton to the electron is 5.29*10^-11 m, and the linear speed of the electron is 2.18*10^6 m/s. (1) what is the angular velocity of the electron? (2) how many orbits about the proton does it make each second? (3) what is the electron's centripetal acceleration?please, help me to solve those questions, thx.
The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the n=1 orbit the distance from the proton to the electron is 5.29*10^-11 m, and the linear speed of the electron is 2.18*10^6 m/s. (1) what is the angular velocity of the electron? (2) how many orbits about the proton does it make each second? (3) what is the electron's centripetal acceleration?please, help me to solve those questions, thx. The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the n=1 orbit the distance from the proton to the electron is 5.29*10^-11 m, and the linear speed of the electron is 2.18*10^6 m/s. (1) what is the angular velocity of the electron? (2) how many orbits about the proton does it make each second? (3) what is the electron's centripetal acceleration?please, help me to solve those questions, thx.

Explanation / Answer

As the force due to coloumb law will provide the centripetal force

K [(q1*q2)/r2] = mrw2

W=K[q1*q2)/mr3]

, w=9*109[(1.6*10-19)2/(9.1*10-31 *(5.29*10-11)3)]

,w=[2.304*10-28]/[1.3471*10-61]

,w=1.71*1033 rad/sec

2- as in 1 sec ,the no of orbits about nucleus(f)=w/2?

,f=2.70*1032 /sec

3-centripetal acceleration

, a =rw2

   , a=(5.29*10-11)*(1.71*1033)2

,    a=1.54*1056 m/sec2

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