5.(4 points) Two straight solenoid inductors have the same physical dimensions.

Question

5.(4 points) Two straight solenoid inductors have the same physical dimensions. Inductor A has half the number of turns that inductor B has. The energy stored in the magnetic field in each inductor is the same as the energy stored in the other's field. How do the currents flowing through the wires of each inductor compare to one another? a) The current in A is twice that in B. b) The current in A is four times that in B. c) The two currents are the same. d) The current in B is twice that in A. e) The current in B is four times that in A.

Explanation / Answer

apply   Ea = Eb

inducced e,mf e =   N L di/dt

as N* i = constant

N2/N1 = i1/i2

i2 = i1 * N1/N2

i2 = i1 * 1/2

answer is option A . i in A is twice that of B

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