Two people carry a heavy electric motor by placing it on a light board 2.40m lon

Question

Two people carry a heavy electric motor by placing it on a light board 2.40m long. One person lifts at one end with a force of 390N , and the other lifts the opposite end with a force of 700N .

Part A

What is the weight of the motor?

Part B

Where along the board is its center of gravity located?

Part C

Suppose the board is not light but weighs 200N , with its center of gravity at its center, and the two people each exert the same forces as before. What is the weight of the motor in this case?

Part D

Where is its center of gravity located?

Explanation / Answer

A) W = 700 + 390 = 1090 N

b) centre of gravity is where moment is zero.

390 x d - 700 x (2.40 - d) = 0

d = 1.54 m from left end.

C) W + 200 = 700+390

W = 890 N

D) centre of gravity is where moment is zero.

390 x d -200 x (d-1.2) - 700 x (2.40 - d) = 0

d =2.16 m

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