1)When an object is placed 17.0 cm to the left of a thin lens the image is 46.0
ID: 1289374 • Letter: 1
Question
1)When an object is placed 17.0 cm to the left of a thin lens the image is 46.0 cm to the right of the lens. What is the focal length of the lens?
2) An object is placed 24.5 cm to the left of a converging lens that has a focal length f1 = +12.9 cm. How far is the image from the lens? (Give your answer to at least one decimal place.)
A screen is placed 51.7 cm to the right of the converging lens. A diverging lens is placed between the converging lens and the screen. When the diverging lens is 14.3 cm to the right of the converging lens the image formed by the lens combination is located at the screen. What is the focal length f2 of the diverging lens?
Explanation / Answer
1)using lens law 1/f = 1/u + 1/v , f= 12.41cm
2) 1/f = 1/u + 1/v, 1/12.9 = 1/24.5 + 1/v => v = 27.245
3) for diverging lens object is the image formed by converging lens and the rays converged act as object hence object distance = 14.3 cm and image distance 51.7cm - 14.3cm = 37.4 cm hence using same lens formula f2= .10.344cm
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.