ORhye-open OHallelujah Rufus Xe LON-CAPA Cours LON-CAPA EquallXe LON-CAPA Speec
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ORhye-open OHallelujah Rufus Xe LON-CAPA Cours LON-CAPA EquallXe LON-CAPA Speec x e LON-CAPA plane X e LON-CAPA Three x e LON-CAPA Three x MCHomework Help XMCHomework Help CHomework Help x MOLoot Crate-Mon x C Mean, Median, M x a bdbe Joseph Raymond Zajac v (Student section: 730 PHY 233B Fall 2014 Messages Courses Help Logout Main Menu Contents Grades O Timer Notes Evaluate Feedback e Print Course Contents HW #8 (11/06 Th 59 PM) Equilibrum point between the Sun and a planet Calculate the point between Jupiter and the Sun at which an object can be placed so that the net gravitational force exerted on it by these two objects is zero. The mass of Jupiter is 1.90x1027 kg, the mass of the Sun is 30 kg and the distance between Jupiter and the sun is 7.78x1011 m. (Give your answer as a distance measured from the planet Submit Answer Tries 0/12 T Post Discussion Send Feedback 7:29 PM 11/2/2014Explanation / Answer
F by juper = F by sun
gm1m2/r^2 = gm1m3/(7.78*10^11-r)^2
1.9*10^27/r^2 = 1.99*10^30/(7.78*10^11 -r)^2
0.23*10^11m =r that is distace from jupiter
r = 0.23*10^11
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